Matematika Sekolah Menengah Atas ∫ (9o² + 2o)do = trkhir -^-​

montydickensulv – June 09, 2023

∫ (9o² + 2o)do =

trkhir -^-​

Penjelasan dengan langkah-langkah:

∫ (9o² + 2o)do

[tex] = \frac{9}{2 + 1} {o}^{2 + 1} + \frac{2}{1 + 1} {o}^{1 + 1} + c[/tex]

[tex] = \frac{9}{3} {o}^{3} + \frac{2}{2} {o}^{2} + c[/tex]

[tex] = \frac{ {9o}^{3} }{3} + \frac{2 {o}^{2} }{2} + c[/tex]

[tex] = {3o}^{3} + {o}^{2} + c[/tex]

= ∫(9o² + 2o)do

= [tex]\frac{9}{2~+~1}~.~o^{2~+~1}~+~\frac{2}{1~+~1}~.~o^{1~+~1}~+~C[/tex]

= [tex]\frac{9}{3}~.~o^{3}~+~\frac{2}{2}~.~o^2~+~C[/tex]

= 3o³ + o² + C

[answer.2.content]